Find the values of sin 37°, sin 53°, tan 37°, and tan 53° in terms of fractions.
Solution
Given
We are required to find the values of:
- sin 37°
- sin 53°
- tan 37°
- tan 53°
Step 1: Consider a Right-Angled Triangle
Let us consider a right-angled triangle △ABC right-angled at B.
- ∠A = 37°
- ∠C = 53°
- Since 37° + 53° = 90°
Step 2: Assume Sides of the Triangle
Take the sides of the triangle in the ratio:
AB : BC : AC = 3 : 4 : 5
- AB = 3 units (opposite to 37°)
- BC = 4 units (adjacent to 37°)
- AC = 5 units (hypotenuse)
Step 3: Find Required Trigonometric Ratios
For angle 37°:
sin 37° = Opposite / Hypotenuse = AB / AC = 3 / 5
tan 37° = Opposite / Adjacent = AB / BC = 3 / 4
For angle 53°:
sin 53° = Opposite / Hypotenuse = BC / AC = 4 / 5
tan 53° = Opposite / Adjacent = BC / AB = 4 / 3
Final Answer
sin 37° = 3/5
sin 53° = 4/5
tan 37° = 3/4
tan 53° = 4/3